Answer:
Explanation:
All the bulbs with have the same resistance.
Let the resistance of the Bulbs all = R
Bulb 1 will get all of the current running through it. There will be a voltage drop of Ed1 = I * R and the voltage left over will be seen by some combination of bulbs 2,3 and 4.
The current will be divided between 2R and R. 2R will get the smaller amount of current, and R will get the larger amount. There will be 3 parts in total.
So 2 and 3 will experience 1/3 I, while the other bulb will get 2/3 I.
The initial voltage is E
The voltage drop seen by bulbs 2,3 and 4 is E - I*R
Bulb 4 will see the entire voltage of E - I*R
Since it sees 2/3 * I The power dissipated by 4 is P4 = (E - I*R) * (2/3)I
Each of the other bulbs see (E - IR) * (1/3 I)/2 as their power dissipation.
So here's the answer.
P1>P4 > (P2 - P3)
P2 = P3 if there is such an answer in C.
