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Write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3. Include all of your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution

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ANSWER

[tex]y-1= \frac{1}{3} (x- 6)[/tex]

EXPLANATION

We want to write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3.

The slope of this line is negative reciprocal of -3.

[tex]m = - \frac{1}{ - 3} = \frac{1}{3} [/tex]

The point-slope form is given by:

[tex]y-y_1=m(x-x_1)[/tex]

We substitute the point and the slope to get;

[tex]y-1= \frac{1}{3} (x- 6)[/tex]

Answer:

y - 1 = 1/3*(x - 6)

Step-by-step explanation:

point-slope form of a line:

y - y1 = m*(x - x1)

where x1 and y1 are the coordinates of the point included in the line and m is its slope.

Two lines are perpendicular when the multiplication of their slopes is equal to -1. In this case,

m*(-3) = -1  

m = 1/3

Replacing this slope and the coordinates of point (6, 1) we get:

y - 1 = 1/3*(x - 6)

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