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The accompanying diagram shows a ramp 30 feet
long leaning against a wall at a construction site.
Wall
If the ramp forms an angle of 32° with the ground,
how high above the ground, to the nearest tenth, is
the top of the ramp?
​

Respuesta :

Using the law of Sin

[tex]\frac{sinA}{a} \frac{sinC}{c}[/tex]

A=32°, a=?

C=90°, c= 30

[tex]\frac{sin32°}{a} = \frac{sin90°}{30}[/tex]

[tex]\frac{30sin32°}{sin90°}[/tex]  = 15.89ft

Rounded answer is 15.9 ft

The height should be 15.89 ft.

Given information:

The accompanying diagrams hows a ramp 30 feet long leaning against a wall at a construction site. And, the ramp forms an angle of 32°

Calculation of height:

Here we applied the law of sin

[tex]sin 32 \div a = sin 90 \div 30\\\\a = 15.89 ft[/tex]

Learn more about the height here: https://brainly.com/question/424967

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