What is the length of AC?

A is at -8 and C i5 at 5
-8 to 0 is 8 units and 0 to 5 is 5 units.
8 +5 = 13
AC is 13 units long.
For this case, we have that by definition, the distance between two points any A and B will be the absolute value of the subtraction of their coordinates in the order that is preferred. (the distances can not be negative)
So:
We find the distance from A to a point x located at 0. ENtonces:
[tex]| -8-0 | = | -8 | = 8[/tex]
Now we add the distance from x to C. From point x (located at zero) to point C there are 5 spaces, then:
[tex]8 + 5 = 13[/tex]
Thus, the distance from A to C is 13
Answer:
13