Answer:
[tex]f^{-1}(x)=\cos^{-1} x+\frac{\pi}{2}[/tex]
Step-by-step explanation:
The given function is
[tex]y=\cos(x-\frac{\pi}{2})[/tex]
To find the inverse of this function, we interchange x and y.
[tex]x=\cos(y-\frac{\pi}{2})[/tex]
Take the inverse cosine of both sides to obtain;
[tex]\cos^{-1} x=y-\frac{\pi}{2}[/tex]
[tex]\cos^{-1} x+\frac{\pi}{2}=y[/tex]
Therefore the inverse of the given cosine function is;
[tex]f^{-1}(x)=\cos^{-1} x+\frac{\pi}{2}[/tex] where [tex]-1\le x\le 1[/tex]
