Answer:
-1.1+0.4i
Step-by-step explanation:
Multiply the numerator and the denominator by [tex]4+2i:[/tex]
[tex]\dfrac{-8+6i}{4-2i}\cdot \dfrac{4+2i}{4+2i}=\dfrac{-32-16i+24i+12i^2}{4^2-(2i)^2}\ \ [\text{use formula }a^2-b^2=(a-b)(a+b)]\\ \\=\dfrac{-32+8i-12}{16-4i^2}\ \ [\text{remember }i^2=-1]\\ \\=\dfrac{-44+8i}{16+4}\\ \\=\dfrac{-44+8i}{20}\\ \\=-\dfrac{11}{10}+\dfrac{4}{10}i\\ \\=-1.1+0.4i[/tex]
