Answer:
amplitude; [tex]\frac{2}{3}[/tex]
Phase shift; [tex]\pi[/tex] units right
Period;[tex]\frac{2\pi}{3}[/tex]
Step-by-step explanation:
The given function is
[tex]y=-\frac{2}{3}\cos(3t-3\pi)[/tex]
This function is of the form;
[tex]y=A\sin (Bt+C)[/tex]
The period is given by:
[tex]|A|=|-\frac{2}{3}|= \frac{2}{3}[/tex]
The period is given by:
[tex]T=\frac{2\pi}{|B|}= \frac{2\pi}{|3|}=\frac{2\pi}{3}[/tex]
The phase shift is given by;
[tex]\frac{C}{B}=\frac{-\3pi}{3}=- \pi[/tex] or [tex]\pi[/tex] units right.
