You were recently hired by a company and will recieve a starting salary of $45,000 per year. You will receive a $2,500 raise each year you are with the company. What will your salary be in your 8th year with the company?

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Answer:

Your salary will be $62,500.

Step-by-step explanation:

This is an arithmetic sequence with first term $45,000 and common difference $2,500.

The appropriate formula is a(n) = a(1) + (n-1)d, where a(1) is the first term, n is a counter and d is the common difference.

In this particular case, a(8) = $45,000 + (8-1)($2,500) = $62,500

Your salary will be $62,500.

A function assigns the values. Your salary after completing the 8th year within the company will be $62,500.

What is a Function?

A function assigns the value of each element of one set to the other specific element of another set.

Given that the starting salary will be $45,000 while the salary will increase every year by $2,500. Therefore, the function that can represent the salary after (n-1) years can be written as,

y = $45,000 + $2,500(n-1)

Now, the salary after 8th year will be,

y = $45,000 + $2,500(n-1)

y = $45,000 + $2,500(8-1)

y = $62,500

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