Answer:
The correct choice is B.
Step-by-step explanation:
The given function is
[tex]f(t)=-\frac{1}{3}\sin (4t-3\pi)[/tex]
The given function is of the form;
[tex]y=A\sin(Bt-C)[/tex]
where
[tex]|A|=|-\frac{1}{3}| =\frac{1}{3}[/tex] is the amplitude.
The period is calculated using the formula;
[tex]T=\frac{2\pi}{|B|}=\frac{2\pi}{|4|}=\frac{\pi}{2}[/tex]
The phase shift is given by;
[tex]\frac{C}{B}=\frac{-3\pi}{4}[/tex]
The correct choice is B
