Answer:
The vertex is the point (3, 6)
Step-by-step explanation:
For a quadratic function [tex]ax ^ 2 + bx + c[/tex] its vertex form is:
[tex]y = a (x-h) ^ 2 + k[/tex]
Where
a is the main coefficient
h is the x coordinate of the vertex
k is the cordage y vertice
Therefore, for a function in this way the vertex will always be the point (h, k)
Notice that for the function
[tex]f (x) = -4 (x-3) ^ 2 + 6\\\\a = -4\\\\h = 3\\\\k = 6[/tex]
Then the vertex is the point (3, 6)
Answer:
(3, 6)
Step-by-step explanation:
Since the question is in y = 1(x-h)^2 +k form and you just put the opposite sign for h making it from 3 to -3.
So far we got x as 3.
and for Y you have k which is 6 so you final answer would be (3,6)
Brainiest would be appreciated.
