Answer:
[tex]18.98\°[/tex]
Step-by-step explanation:
Let
x-----> the angle of depression
we know that
The sine of angle x is equal to divide the altitude (opposite side to angle x) by the distance from the runway (hypotenuse)
[tex]sin(x)=\frac{2.7}{8.3}[/tex]
[tex]x=arcsin(\frac{2.7}{8.3})=18.98\°[/tex]
Answer:
18.02°
Step-by-step explanation:
Formula to find angle of depression is given as
tan y = opposite / adjacent
where y = angle of depression
Where opposite = height or altitude of a person or thing
adjacent = distance
In this question ,
opposite = altitude of the plane = 2.7 miles
adjacent = distance of the plane from the runaway = 8.3 miles
Angle of depression is calculated as
tan y = ( 2.7/8.3)
y = tan⁻¹ ( 2.7÷8.3)
y = 18.02°
Angle of depression that the plane must make to land safely = 18.02°
