Answer:
Step-by-step explanation:
First, you need to make these conversions:
(Remember that [tex]1m=100cm[/tex])
4,000 cm to m:
[tex](4,000cm)(\frac{1m}{100cm})=40m[/tex]
700 cm to m:
[tex](700cm)(\frac{1m}{100cm})=7m[/tex]
You can observe in the figure that it is formed by two rectangles and a semi-circle.
To calculate the perimeter, you need to add the exterior measures of each figure.
Remember that the circumference of a circle is:
[tex]C=2\pi r[/tex]
Where "r" is the radius
Therefore, the perimeter is:
[tex]P=34m+7m+10m+40m+10m+68m+33m+\frac{(2\pi (17m)}{2}\\P=255.40m[/tex]
To find the area of the indoor sports exhibition, you need to add the areas of the rectangles and the area of the semi-circle.
The area of a rectangle can be calculated with:
[tex]A_r=lw[/tex]
Where "l" is the lenght and "w" is the width.
The area of a semi-circle can be calculated with:
[tex]A_{sc}=\frac{\pi r^2}{2}[/tex]
Where "r" is the radius.
Then, the area of the indoor sports exhibition is:
[tex]A=(40m)(10m)+(68m)(33m)+\frac{\pi (17m)^2}{2}\\A=3,097.96m^2[/tex]
