Answer:
3; [tex]f(n)=2(3)^{n-1}[/tex]
Step-by-step explanation:
The given sequence is
2, 6, 18, 54,....
The first term is [tex]f(1)=2[/tex]
The common ratio is obtained expressing a subsequent term over a previous term.
The common ratio is [tex]r=\frac{6}{2} =3[/tex]
The the nth term of the sequence is given by:
[tex]f(n)=f(1)(r^{n-1})[/tex]
[tex]f(n)=2(3)^{n-1}[/tex]
The exponential function which represents the sequence is
[tex]f(n)=2(3)^{n-1}[/tex]
