Find the surface area of the right square pyramid. Round your answer to the nearest hundredth.

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kudzordzifrancis kudzordzifrancis · Answer 1 · 2019-05-08T02:05:24+02:00

ANSWER

C. 145.75 yd²

EXPLANATION

First we need to calculate the area of the four triangular faces.

The lateral surface area

[tex] = 4 \times \frac{1}{2} \times 5.3 \times 11.1[/tex]

[tex] = 117.66 {yd}^{2} [/tex]

The area of the base is

[tex] = 5.3 \times 5.3[/tex]

[tex] = 28.09[/tex]

To find the total surface area, we add the area of the square base to the area of the 4 triangular faces.

Therefore the total surface area is

[tex] = 117.66 + 8.09 = 145.75 {yd}^{2} [/tex]

luisejr77 luisejr77 · Answer 2 · 2019-05-08T02:09:39+02:00

Answer: Option C.

Step-by-step explanation:

To calculate the surface area of the right square pyramid, you need to use the following formula:

[tex]SA=\frac{1}{2}(4s)(l)+(s^2)[/tex]

Where "s" is the length of any side of the base and "l" is the slant height.

You can identify in the figure that:

[tex]s=5.3yd\\l=11.1yd[/tex]

Therefore, substituting these values into the formula, you get this result:

[tex]SA=\frac{1}{2}(4(5.3yd))(11.1yd)+((5.3yd)^2)\\\\SA=145.75yd^2[/tex]