For this case we have the following functions:
[tex]f (x) = x ^ 2-6x + 8\\g (x) = x-2[/tex]
We must subtract the functions:
[tex]f (x) -g (x) = x ^ 2-6x + 8- (x-2)\\f (x) -g (x) = x ^ 2-6x + 8-x + 2\\f (x) -g (x) = x ^ 2-7x + 10[/tex]
We build a table of values for [tex]x = 0,1,2,3.[/tex]
[tex]x = 0, f (x) -g (x) = 0 ^ 2-7 (0) + 10 = 10\\x = 1, f (x) -g (x) = 1 ^ 2-7 (1) + 10 = 1-7 + 10 = 4\\x = 2, f (x) -g (x) = 2 ^ 2-7 (2) + 10 = 4-14 + 10 = 0\\x = 3, f (x) -g (x) = 3 ^ 2-7 (3) + 10 = 9-21 + 10 = -2[/tex]
Answer:
[tex]f (x) -g (x) = x ^ 2-7x + 10[/tex]
