Answer:
Step-by-step explanation:
To do this, we must use the unit circle. At the angle [tex]\frac{\pi }{6}[/tex] the coordinate pair is ([tex]\frac{\sqrt{3} }{2}[/tex], [tex]\frac{1}{2}[/tex]) and the hypotenuse is 1
Now that we know these we can start using the trig functions
sin = y
cos = x
tan = [tex]\frac{y}{x}[/tex]
And the other functions would be the reciprocal of these
csc = [tex]\frac{1}{y}[/tex]
sec = [tex]\frac{1}{x}[/tex]
cot = [tex]\frac{x}{y}[/tex]
This would mean that
sinx = [tex]\frac{1}{2}[/tex]
cosx =[tex]\frac{\sqrt{3} }{2}[/tex]
tanx =[tex]\frac{1}{\sqrt{3} }[/tex] or [tex]\frac{\sqrt{3} }{3}[/tex] if you're supposed to rationalize your denominators
cscx = 2
secx = [tex]\frac{2}{\sqrt{3} }[/tex] or [tex]\frac{2\sqrt{3} }{3}[/tex]
cot = [tex]\sqrt{3}[/tex]
