Answer:
The probability that a point randomly chose in the rectangle is in the triangle is [tex]\frac{1}{8}[/tex], so the answer would be A
Step-by-step explanation:
To find the probability of a random point being in the triangle, we must find the area of the triangle and the area of the rectangle.
The area of the rectangle can be found by multiplying the width by the height, so the equation would be
[tex]8 *4 = 32[/tex]
The area of the the triangle can be found by the formula [tex]A = \frac{1}{2} bh[/tex]
This means that the equation would look like
[tex]\frac{1}{2} *2*4=4[/tex]
Now that we have both the area of the triangle and the rectangle, we can create a ration of the area of the triangle to that of the rectangle. It would look like this
[tex]\frac{4}{32}[/tex]
This would simplify to [tex]\frac{1}{8}[/tex]
