Answer:
image 1
Step-by-step explanation:
Given data:
f(x) = (x+3)(x-2)
= x^2 + x-6
As the given expression is a quadratic expression so the graph will be parabola.
Also coefficient of x^2 is 1, 1>0 hence we'll the parabola opens upwards
that reduces our options to image 1 and 2 only
now to find the x-axis points of parabola
let (x+3)(x-2)=0
(x+3)=0 and (x-2)=0
x= -3 and x= 2
when at y=0, x= -3 and x=2
hence the image 1 !
