Answer:
[tex]2.2\cdot 10^{-3} \Omega[/tex]
Explanation:
The resistance of the lead block is given by
[tex]R=\frac{\rho L}{A}[/tex]
where
[tex]\rho = 2.2\cdot 10^{-5}\Omega cm[/tex] is the resistivity of lead
[tex]L = 10 cm[/tex] is the length of the block
[tex]A=0.10 cm^2[/tex] is the cross sectional area of the block
Substituting into the equation, we find
[tex]R=\frac{(2.2\cdot 10^{-5} \Omega cm)(10 cm)}{0.10 cm^2}=2.2\cdot 10^{-3} \Omega[/tex]
