Respuesta :
Answer:
The perimeter = 26 unites
Step-by-step explanation:
* Lets revise some facts of parallelogram
- Every two opposite sides are parallel and equal
- Every two opposite angles are equal
- Every two adjacent angles are supplementary
- Th two diagonals bisects each other
- The perimeter = 2(S1 + S2)
* Now lets solve the problem
- ABCD is a parallelogram, where
A = (-2 , 6) , B = (1 , 2) , C = (-2 , -2) , D = (1 , -6)
- To find the perimeter we need the length of AB and BD
- The rule of the distance between two point is
d = √[(x2 - x1)² + (y2 - y1)²]
* Lets find AB
∵ AB = √[1 - -2)² + (2 - 6)²] = √[(3²) + (-4)²]
∴ AB = √25 = 5
* Lets find BD
∵ BD = √[(1 - 1)² + (-6 - 2)² = √[(0)² + (-8)²]
∴ BD = √64 = 8
* Lets find the perimeter
∵ The perimeter = 2 (5 + 8) = 26 unites
Answer:
26 units
Step-by-step explanation:
The attached image shows the coordinates drawn as a parallelogram.
The perimeter is sum of all the sides, AB + BD + DC + CA
Both BD and CA are straight lines with 8 units
AB and DC are not straight lines. So we need to find it using the pythagorean theorem, which is , one leg squared of a triangle + another leg squared will give us hypotenuse squared.
Looking at the triangle AYB, we can write and solve for AB:
[tex]AY^2+YB^2=AB^2\\4^2 + 3^2 = AB^2\\16+9=AB^2\\25=AB^2\\AB=5[/tex]
we can use the same argument and lengths for the triangle CXD. We will have DC = 5 units
Perimeter = AB + BD + DC + CA = 5 + 8 + 5 + 8 = 26 units