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A fireworks company has two types of rockets called Zinger 1 and Zinger 2. The polynomial -16t^2 + 150t gives the height in feet of Zinger 1 at t seconds after launch. The polynomial -16t^2 + 165t gives the height of Zinger 2 at t seconds after launch. If the rockets are launched at the same time and both explode 6 seconds after launch, how much higher is Zinger 2 than Zinger 1 when they explode? 414 ft

90 ft

324 ft

990 ft

Respuesta :

TaeKwonDoIsDead

Answer:

90 feet

Step-by-step explanation:

If we put t  = 6 into both the formulas, we will get the height of each.

Zinger 1:

Height = [tex]-16t^2 + 150t[/tex]

Putting t = 6,

[tex]-16(6)^2 + 150(6)=324[/tex]

Zinger 2:

Height = [tex]-16t^2 + 165t[/tex]

Putting t = 6,

[tex]-16(6)^2 + 165(6)=414[/tex]

The difference in height is 414 - 324 = 90 feet

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