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An experiment consists of randomly selecting a marble from a bag, keeping it, and then selecting another marble. The bag contains 4 blue marbles, 3 green marbles, 7 red marbles, and 1 yellow marble. What is the probability of selecting a red marble and then a blue marble? Question 3 options: 20% 13.33% 10% 16.66%

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Answer:

13.33%

Step-by-step explanation:

First we need to find the total number of marbles

4 blue marbles+ 3 green marbles+ 7 red marbles+ 1 yellow marble= 15

The probability of a red marble = number of red marbles over the total marbles

P(red) = red/total = 7/15

We keep the marble.  There are now 6 red marbles

4 blue marbles+ 3 green marbles+ 6 red marbles+ 1 yellow marble= 14

We have 14 marbles in the bag

The probability of a blue marble = number of blue marbles over the total marbles

P(blue) = blue/total = 4/14 = 2/7

Then we multiply the probabilities together

P(red,blue0 = 7/15 * 2/7 = 2/15 =.13333333 = 13.33%

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