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Modern oil tankers weigh over a half-million tons and have lengths of up to one-fourth miles. Such massive ships require a distance of 5.3 km (about 3.3 mi) and a time of 22 min to come to a stop from a top speed of 29 km/h. What is the magnitude of such a ship’s average acceleration in m/s^2 in coming to a stop? What is the magnitude of the ship’s average velocity in m/s?

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Answer:

Acceleration = (change in speed) / (time for the change)

Change in speed= (0 - 26 km/hr) = -26 km/hr

(-26 km/hr) x (1,000 m/km) x (1 hr / 3,600 sec) = -7.222 m/sec

Average acceleration = (-7.222 m/s) / (22 min x 60sec/min) = -0.00547 m/sec²

Average speed during the stopping maneuver =

              (1/2) (start speed + end speed) = 13 km/hr = 3.6111 m/sec

Explanation:

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