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A group of 10 students participate in chess club, karate club, or neither. Let event A = The student is in karate club. Let event B = The student is in chess club.


One of these students is randomly selected. What is P(A/B)?

A group of 10 students participate in chess club karate club or neither Let event A The student is in karate club Let event B The student is in chess club One o class=
A group of 10 students participate in chess club karate club or neither Let event A The student is in karate club Let event B The student is in chess club One o class=

Respuesta :

ShyzaSling

Answer:

option A

2/4 = 0.5

Step-by-step explanation:

Given in the questions that,

number of student in chess club = 4

P(B) = 4/10

number of student in karate club = 6

P(A) = 6/10

number of students who are both in chess and karate club = 2

P(A∩B) = 2/10

total number of students 10

Formula to use

P(A/B) = P(A∩B) / P(B)

           = 2/10 / 4/10

           = 2/4

           = 1/2

           = 0.50

Answer:

2/4 or 50%

Step-by-step explanation:

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