Answer:
Mass of 50 moles of tin(II) sulfate is 10,738 grams.
Explanation:
[tex]n=\frac{m}{M}[/tex]
Where:
n = moles of compound
m = mass of compound
M = molar mass of the compound
Moles of tin(II) sulfate , n= 50 moles
Molar mass of tin (II) sulfate , M= 214.77 g/mol
m = n × M
[tex]m=50 moles \times 214.77 g/mol=10,738 g[/tex]
Mass of 50 moles of tin(II) sulfate is 10,738 grams.
