Find the surface area of a right prism whose bases are equilateral triangles with side lengths of 6in. The height of the prism is 10in

ANSWER
[tex]211.2 {in}^{2} [/tex]
EXPLANATION
The surface area of a triangular prism is
equal to the area of two triangular faces
plus the area of the three rectangular faces.
The area of the equilateral triangle is calculated using the formula:
[tex] = 2 \times \frac{ \sqrt{3} }{4} {s}^{2} + 3 \times \: bh[/tex]
where s=6 is the length of one side.
and b=6 is the breadth of the rectangle and h=10 is the height of the rectangle.
Surface area
[tex]= 2 \times \frac{ \sqrt{3} }{4} \times {6}^{2} + 3 \times \: 6 \times 10[/tex]
[tex]= 18\sqrt{3} + 180[/tex]
=211.2square inches.