Heat of vapourrisation required to( change the state) of water is 2260 J/grm.
Answer : The heat of vaporization is, 924.7 joules/gram.
Explanation :
Formula used for heat of vaporization :
[tex]H_{Vap}=\frac{q}{m}[/tex]
where,
[tex]H_{Vap}[/tex] = heat of vaporization = ?
q = required heat = 8720 J
m = mass of substance = 9.43 g
Now put all the given values in the above formula, we get :
[tex]H_{Vap}=\frac{8720J}{9.43g}=924.7J/g[/tex]
Therefore, the heat of vaporization is, 924.7 joules/gram.
