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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

A spinner has five equal sections that are numbered 1 through 5.

In which distributions does the variable X have a binomial distribution?

Select EACH correct answer.




When the spinner is spun three times, X is the sum of the numbers the spinner lands on.

When the spinner is spun multiple times, X is the number of spins until it lands on 5.

When the spinner is spun four times, X is the number of times the spinner does not land on an odd number.

When the spinner is spun five times, X is the number of times the spinner lands on 1.

PLEASE HELP ASAP CORRECT ANSWER ONLY PLEASE A spinner has five equal sections that are numbered 1 through 5 In which distributions does the variable X have a bi class=

Respuesta :

Answer:  C & D

Step-by-step explanation:

A binomial experiment must satisfy ALL four of the following:

  1.  A fixed number of trials
  2.  Each trial is independent of the others
  3.  There are only two outcomes (Success & Fail)
  4.  The probability of each outcome remains constant from trial to trial.

A) When the spinner is spun three times, X is the sum of the numbers the spinner lands on.

  → #3 is not satisfied  (#4 is also not satisfied)

B) When the spinner is spun multiple times ...

    → #1 is not satisfied

C)  When the spinner is spun four times, X is the number of times the spinner does not land on an odd number.

    → Satisfies ALL FOUR

  1.  A fixed number of trials = 4
  2.  Each trial is independent of the others = each spin is separate
  3.  There are only two outcomes = Not Odd & Odd
  4.  The probability of each outcome remains constant from trial to trial = P(X = not odd) = 0.50 for each spin

D) When the spinner is spun five times, X is the number of times the spinner lands on 1.

   → Satisfies ALL FOUR

  1.  A fixed number of trials = 5
  2.  Each trial is independent of the others = each spin is separate
  3.  There are only two outcomes = 1 & Not 1
  4.  The probability of each outcome remains constant from trial to trial = P(X = 1) = 0.17 for each spin