Answer:
[tex](x-5)^2 + (y-3)^2= 16[/tex] is the equation of a circle
Step-by-step explanation:
The circle below is centered at the point (5,3) and has a radius of length 4
To find the center form of equation, we use formula
[tex](x-h)^2 + (y-k)^2= r^2[/tex]
where (h,k) is the center and 'r' is the radius of the circle
given center is (5,3)
h=5 and k =3
radius r= 4, plug in all the values in the equation
[tex](x-h)^2 + (y-k)^2= r^2[/tex]
[tex](x-5)^2 + (y-3)^2= 4^2[/tex]
[tex](x-5)^2 + (y-3)^2= 16[/tex] is the equation of a circle
