Answer:
The LCM will be: [tex]10x^3y^3[/tex]
and The Solution will be: [tex]\frac{12y^2-5x}{10x^3y^3}[/tex]
Step-by-step explanation:
We need to solve the problem
[tex]\frac{6}{5x^3y}-\frac{1}{2x^2y^3}[/tex]
Since there is minus sign, so we take LCM of 5x^3y and 2x^2y^3
The LCM will be: [tex]10x^3y^3[/tex]
Our equation will become after taking LCM
[tex]=\frac{12y^2}{10x^3y^3}-\frac{5x}{10x^3y^3}\\=\frac{12y^2-5x}{10x^3y^3}[/tex]
