Which points are on the plane curve described by the following set of parametric equations? Select TWO

X = 4t + 3 and Y = 5t^2

Answer Choices:

(-1 , -5)
(-1 , 5)
(1 , 7)
(2 , 11)
(7 , 5)

Respuesta :

ANSWER

(-1,5)

(7,5)

EXPLANATION

The given set of parametric equations is:

[tex]x = 4t + 3[/tex]

and

[tex]y = 5 {t}^{2} [/tex]

We make t the subject in the first equation to get:

[tex]t = \frac{x - 3}{4} [/tex]

We put this into the second equation to get;

[tex]y =5( \frac{x - 3}{4} )^{2} [/tex]

When x=-1,

[tex]y =5( \frac{ - 1- 3}{4} )^{2} = 5[/tex]

Therefore (-1,5) lies on this line.

When x=7,

[tex]y =5( \frac{7 - 3}{4} )^{2} = 5[/tex]

Therefore (7,5) also lie on this line.