Respuesta :

Answer: 82

Simply pug in 6 for [tex]x[/tex]

[tex]2(6)^2+5\sqrt{(6-2)} \\72+5\sqrt{4} \\72+5(2)\\72+10=\\82[/tex]

Hope this helps and have a great day!!!

[tex]Sofia[/tex]

For this case we have a function of the form [tex]y = f (x).[/tex]

Where:[tex]f (x) = 2x ^ 2 + 5 \sqrt {x-2}[/tex]

We must find the value of the function when x = 6, that is, f (6):

Then, replacing the value of "x"[tex]f (6) = 2 (6) ^ 2 + 5 \sqrt {6-2}\\f (6) = 2 * 36 + 5 \sqrt {4}\\f (6) = 72 + 5 (2)\\f (6) = 72 + 10\\f (6) = 82[/tex]

So, [tex]f (6) = 82[/tex]

ANswer:

[tex]f (6) = 82[/tex]