Respuesta :
Answer: 82
Simply pug in 6 for [tex]x[/tex]
[tex]2(6)^2+5\sqrt{(6-2)} \\72+5\sqrt{4} \\72+5(2)\\72+10=\\82[/tex]
Hope this helps and have a great day!!!
[tex]Sofia[/tex]
For this case we have a function of the form [tex]y = f (x).[/tex]
Where:[tex]f (x) = 2x ^ 2 + 5 \sqrt {x-2}[/tex]
We must find the value of the function when x = 6, that is, f (6):
Then, replacing the value of "x"[tex]f (6) = 2 (6) ^ 2 + 5 \sqrt {6-2}\\f (6) = 2 * 36 + 5 \sqrt {4}\\f (6) = 72 + 5 (2)\\f (6) = 72 + 10\\f (6) = 82[/tex]
So, [tex]f (6) = 82[/tex]
ANswer:
[tex]f (6) = 82[/tex]