ANSWER
B. 700 units^2
EXPLANATION
The surface area of the pyramid is the area of the four triangular faces plus the area of the square base.
The area of the four triangular faces is
[tex] = 4 \times \frac{1}{2} \times bh[/tex]
We substitute b=14 and h=18.
[tex] = \frac{1}{2} \times 14 \times 18 \times 4[/tex]
[tex] =504 {units}^{2} [/tex]
The area of the square base
[tex] = {14}^{2} = 196 {units}^{2} [/tex]
The surface area of the pyramid is
[tex] = 196 + 504 = 700 {units}^{2} [/tex]
