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Which equation represents a line that passes through (–9, –3) and has a slope of –6?

y – 9 = –6(x – 3)
y + 9 = –6(x + 3)
y – 3 = –6(x – 9)
y + 3 = –6(x + 9)

Respuesta :

RogersJustin12

Answer:

y+3= -6(x+9) is the answer

Step-by-step explanation:

lublana

Answer:

[tex]y+3=-6(x+9)[/tex]

Step-by-step explanation:

We are given that

Slope of a line=-6

Given point =(-9,-3)

We have to find the equation which represents the line.

The equation of line passing through the given point [tex](x_1,y_1)[/tex] with slope m is given by

[tex]y-y_1=m(x-x_1)[/tex]

Substitute the values then we get

The equation of line passing through the point (-9,-3) with slope -6 is given by

[tex]y-(-3)=-6(x-(-9))[/tex]

[tex]y+3=-6(x+9)[/tex]

Hence, the equation of line that passes through (-9,-3) and has  a slope -6 is given by

[tex]y+3=-6(x+9)[/tex]

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