Can someone please help me

Answer:
Step-by-step explanation:
Lateral Area:
We have four congruent triangles with base b = 16cm and height h = 12cm.
The formula of an area of a traingle:
[tex]A_\triangle=\dfrac{bh}{2}[/tex]
Substitute:
[tex]A_\triangle=\dfrac{(16)(12)}{2}=(8)(12)=96\ cm^2[/tex]
[tex]L.A.=4A_\triangle=4(96)=384\ cm^2[/tex]
Surface Area:
[tex]S.A.=B+L.A.[/tex]
In the base we have the square with side s = 16cm. The formula of an area of a square:
[tex]A_\square=s^2[/tex]
Substitute:
[tex]B=16^2=256\ cm^2[/tex]
[tex]S.A.=256\ cm^2+384\ cm^2=640\ cm^2[/tex]