Answer:
The standard error of the proportion is
[tex]E=0.089[/tex]
Step-by-step explanation:
Assuming that the size of population N is large enough, and with a sample [tex]n = 30[/tex], so that:
[tex]\frac{n}{N}\leq0.05[/tex] then the standard error of the proportion is:
[tex]E = \sqrt{\frac{p(1-p)}{n}}[/tex]
Where
[tex]n = 30\\\\p= 0.6\\\\E = \sqrt{\frac{0.6(1-0.6)}{30}}\\\\E =\sqrt{\frac{0.6(0.4)}{30}}\\\\E=\frac{\sqrt{5}}{25}=0.089[/tex]
