Answer:
14 m/s
Explanation:
The motion of the book is a free fall motion, so it is an uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. Therefore we can find the final velocity by using the equation:
[tex]v^2 = u^2 + 2gd[/tex]
where
u = 0 is the initial speed
g = 9.8 m/s^2 is the acceleration
d = 10.0 m is the distance covered by the book
Substituting data, we find
[tex]v=\sqrt{0^2 + 2(9.8 m/s^2)(10.0 m)}=14 m/s[/tex]
