Answer:
[tex]\lim_{x \to \infty} \frac{2500+17(x-100)}{x}=17[/tex]
Step-by-step explanation:
Let the theme park sold number of tickets = x
Theme park charges $500 for group booking more than 25 tickets.
In addition to this theme park charges $20 per ticket for up to 100 tickets.
So charges of 100 tickets = 500 + (100×20) = $2500
For more than 100 tickets theme park charges $17, so charges for x tickets will be = 500 + (100×20) + 17(x - 100)
= 2500 + 17(x - 100)
Cost of one ticket of the theme park = [tex]\frac{2500+17(x-100)}{x}[/tex]
Now we have to write the limit equation when number of tickets purchased becomes very high.
[tex]\lim_{x \to \infty} \frac{2500+17(x-100)}{x}=17[/tex]
[By solving limit as below
[tex]\lim_{x \to \infty} \frac{2500+17(x-100)}{x}= \lim_{x \to \infty}\frac{2500}{x}+17-\frac{1700}{x}[/tex]
since [tex]\lim_{x \to \infty}(\frac{1}{x})=0[/tex]
Therefore, [tex]\lim_{x \to \infty}\frac{2500}{x}+17-\frac{1700}{x}=0+17-0[/tex]
= 17 ]