How much heat energy is absorbed when 41.5g of ice melts at STP? (Picture Attached)

Answer:
= 13.857 kJ
Explanation:
The heat required to melt ice from its solid state to water or liquid states without change in temperature is given by the formula;
Heat = mLf ; where m is the mass of ice and Lf is the latent heat of fusion,
The mass of ice in moles = 41.5 g/18 g
= 2.306 moles
Therefore;
Heat = 2.306 moles × 6.009 kJ/mol
= 13.857 kJ