Answer:
x = 1/4 and y = -2
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}y=-8x&(1)\\4x-y=3&(2)\end{array}\right\qquad\text{put (1) to (2):}\\\\4x-(-8x)=3\\4x+8x=3\\12x=3\qquad\text{divide both sides by 12}\\x=\dfrac{3}{12}\to x=\dfrac{1}{4}\\\\\text{put the value of x to (1):}\\\\y=-8\left(\dfrac{1}{4}\right)=-2[/tex]
