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a rock dropped on the moon will increases its speed from 0 m/s (its starting speed when first dropped) to 4.9 m/s in about 3 seconds. What value do your calculate for the magnitude of the acceleration of gravity on the moon?

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ShyzaSling

Answer:

a = 1.63 m/s²

Explanation:

Given in the question that,

initial speed of the rock = u = 0 m/s

final speed of the rock = v = 4.9 m/ s

time taken = t = 3 sec

We will use Newton's law of motion

Formula to use to calculate the acceleration of gravity on moon

v - u = a(t)

4.9 - 0 = a(3)

4.9 = a(3)

a = 4.9/3

a = 1.63 m/s²

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