Respuesta :
Answer:
Step-by-step explanation:
Set up hypotheses as:
[tex]H-0: p=0.60\\H_a: p >0.60[/tex]
(Right tailed test)
Sample proportion p = favourable/total = [tex]\frac{640}{1000} =0.64[/tex]
p difference [tex]=0.64-0.60 =0.04[/tex]
Sample std error = [tex]\sqrt{\frac{pq}{n} } =\sqrt{\frac{0.64(0.36)}{1000} } \\=0.0152[/tex]
Critical value for95% = 1.96
Margin of error = [tex]1.96(0.0152)\\= 0.0298[/tex]
Confidence interval for proportions
=[tex](0.64-0.0298, 0.64+0.0298)\\=(0.6102,0.6698)[/tex]
Since confidence interval does not contain 0.60 we reject null hypothesis.
At 5% significance level we can accept thta proportion >0.60