Compare the three functions below. Which has a greater period? A) y = 3cos(2x+1), B) y=5cos(4x +8), and C) y=cos(2x+4) (4.3)

Respuesta :

Step-by-step explanation:

Given functions are

A) y = 3cos(2x+1), B) y=5cos(4x +8), and C) y=cos(2x+4) (4.3)

or we can rewrite :

A) y = 3cos(2x+1), B) y=5cos(4x +8), and C) y=(4.3)cos(2x+4)

We need to find their periods which is basically (2pi/coefficient of x) of  the given cosine function.

So the period of given choices are:

A) [tex]\frac{2\pi}{2}[/tex], B) [tex]\frac{2\pi}{4}[/tex], and C) [tex]\frac{2\pi}{2}[/tex]

or

A) [tex]\pi[/tex], B) [tex]\frac{\pi}{2}[/tex], and C) [tex]\pi[/tex]

Greatest of them is [tex]\pi[/tex]

So the correct choice is A) y = 3cos(2x+1) and C) y=cos(2x+4) (4.3)