Answer:
Final answer is [tex]\frac{21x-7}{3x^2-2}[/tex]
Step-by-step explanation:
We have been given two terms [tex]\frac{21x}{3x^2-2}[/tex]
and [tex]\frac{7}{3x^2-2}[/tex]
Now we need to find their difference. So let's subtract them
[tex]\frac{21x}{3x^2-2}-\frac{7}{3x^2-2}[/tex]
Denominators are equal so we can easily subtract numerators
[tex]=\frac{21x-7}{3x^2-2}[/tex]
We may factor the numerator but we won't get any factor in denominator that can be cancelled with numerator.
Hence final answer is [tex]\frac{21x-7}{3x^2-2}[/tex]
