Answer:
Equation B.
Step-by-step explanation:
These are all quadratic equations, which are solved through the quadratic formula:
[tex]\frac{-b+-\sqrt{b^2 -4ac}}{2a}[/tex]
where a is the coefficient of our second degree term (the number that is multiplying [tex]x^2[/tex]), b is the coefficient of our first degree term (the number multiplying [tex]x[/tex]), and c is our independent term (the number that is not accompanied by any [tex]x[/tex]).
Quadratic equations can have either one, two or zero solutions. To find hem, we simply plug the coefficients into the formula (For example: in our first equation, [tex]a=1[/tex], [tex]b=14[/tex], [tex]c=-40[/tex]).
Repeating this process in all four equations, we get that there is only one equation that meets our conditions:
Equation B. Solutions: [tex]x=4[/tex] and [tex]x=10[/tex]
