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A rectangular porch has dimensions of (2x+3) feet and (x+9) feet. the area of the porch is 500 square feet. what are the length and width of the porch?

Respuesta :

Answer:

The dimensions of the porch are [tex]25\ ft[/tex]  by [tex]20\ ft[/tex]

Step-by-step explanation:

we know that

The area of the porch is equal to the length multiplied by the width

[tex]A=(2x+3)(x+9)[/tex]

[tex]A=500\ ft^{2}[/tex]

so

[tex]500=(2x+3)(x+9)[/tex]

Solve for x

[tex]500=2x^{2} +18x+3x+27\\ \\2x^{2} +21x-473=0[/tex]

Solve the quadratic equation by graphing

The solution is [tex]x=11\ ft[/tex]

see the attached figure

The dimensions are

[tex](2x+3)=2(11)+3=25\ ft[/tex]

[tex](x+9)=11+9=20\ ft[/tex]

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