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Answer:
[tex][B]=2[/tex]
Step-by-step explanation:
[tex]B=\left[\begin{array}{ccc}3x-5&-3+2y\\11-3x&2y-5\end{array}\right][/tex]
With [tex]x=3[/tex] and [tex]y=4[/tex]
[tex]B=\left[\begin{array}{ccc}3(3)-5&-3+2(4)\\11-3(3)&2(4)-5\end{array}\right][/tex]
[tex]B=\left[\begin{array}{ccc}9-5&-3+8\\11-9&8-5\end{array}\right][/tex]
[tex]B=\left[\begin{array}{ccc}4&5\\2&3\end{array}\right][/tex]
solving the determinant of matrix B
[tex][B]=\left[\begin{array}{ccc}4&5\\2&3\end{array}\right]=(4.3-5.2)=(12-10)=2[/tex]