Answer:
[tex]\sqrt{7}[/tex]
Step-by-step explanation:
let the other leg be x
Then using Pythagoras' identity
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 3² = 4²
x² + 9 = 16 ( subtract 9 from both sides )
x² = 7 ( take the square root of both sides )
x = [tex]\sqrt{7}[/tex]
