Respuesta :

Cxlver

Answer:

[tex](\pm \sqrt{2}, 0)[/tex]

Step-by-step explanation:

The x intercepts are basically the points at which y = 0.

-x^2 + 2 = 0

-x^2 = -2

x^2 = 2

x = [tex]\pm \sqrt{2}[/tex]

carlosego

For this case we have by definition, that to find the x-intercept points, we must make the variable y = 0 and clear the value of "x". So:

[tex]y = -x ^ 2 + 2\\0 = -x ^ 2 + 2\\x ^ 2 = 2\\x = \sqrt {2}[/tex]

So, the x-intercepts are:

[tex](x_ {1}, y_ {1}) = (\sqrt {2}, 0)\\(x_ {2}, y_ {2}) = (- \sqrt {2}, 0)[/tex]

ANswer:

[tex](x_ {1}, y_ {1}) = (\sqrt {2}, 0)\\(x_ {2}, y_ {2}) = (- \sqrt {2}, 0)[/tex]

Otras preguntas