The magnetic field around a current carrying wire at a distance of 1cm is twice as strong as 2cm . How does the Ford strength at 0.5cm compare to the field strength at 1cm

Respuesta :

Answer:

It is half the field strength at 0.5cm

Explanation:

The comparison of magnetic fields at two places is required.

The magnetic field at 0.5 cm is twice as strong compared to the magnetic field at 1 cm.

Magnetic field is given by

[tex]B=\dfrac{\mu_0I}{2\pi r}[/tex]

[tex]\mu_0[/tex] = Vacuum permeability

I = Current

r = Radial distance

So,

[tex]B\propto \dfrac{1}{r}[/tex]

[tex]B_{0.5}=\dfrac{1}{0.5}[/tex]

[tex]B_1=\dfrac{1}{1}=1[/tex]

[tex]\dfrac{B_{0.5}}{B_1}=\dfrac{1}{0.5}\\\Rightarrow B_{0.5}=2B_1[/tex]

So, the magnetic field at 0.5 cm is twice as strong compared to the magnetic field at 1 cm.

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